0=y2+9y+14

Solution for 0=y2+9y+14 equation:

0=y2+9y+14

We move all terms to the left:

0-(y2+9y+14)=0

We add all the numbers together, and all the variables

-(+y^2+9y+14)+0=0

We add all the numbers together, and all the variables

-(+y^2+9y+14)=0

We get rid of parentheses

-y^2-9y-14=0

We add all the numbers together, and all the variables

-1y^2-9y-14=0

a = -1; b = -9; c = -14;
Δ = b2-4ac
Δ = -92-4·(-1)·(-14)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-5}{2*-1}=\frac{4}{-2}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+5}{2*-1}=\frac{14}{-2}
=-7
$