0y-5(1+y)=3(2y-2)-20

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Solution for 0y-5(1+y)=3(2y-2)-20 equation:


Simplifying
0y + -5(1 + y) = 3(2y + -2) + -20

Anything times zero is zero.
0y + -5(1 + y) = 3(2y + -2) + -20
0 + (1 * -5 + y * -5) = 3(2y + -2) + -20
0 + (-5 + -5y) = 3(2y + -2) + -20

Combine like terms: 0 + -5 = -5
-5 + -5y = 3(2y + -2) + -20

Reorder the terms:
-5 + -5y = 3(-2 + 2y) + -20
-5 + -5y = (-2 * 3 + 2y * 3) + -20
-5 + -5y = (-6 + 6y) + -20

Reorder the terms:
-5 + -5y = -6 + -20 + 6y

Combine like terms: -6 + -20 = -26
-5 + -5y = -26 + 6y

Solving
-5 + -5y = -26 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
-5 + -5y + -6y = -26 + 6y + -6y

Combine like terms: -5y + -6y = -11y
-5 + -11y = -26 + 6y + -6y

Combine like terms: 6y + -6y = 0
-5 + -11y = -26 + 0
-5 + -11y = -26

Add '5' to each side of the equation.
-5 + 5 + -11y = -26 + 5

Combine like terms: -5 + 5 = 0
0 + -11y = -26 + 5
-11y = -26 + 5

Combine like terms: -26 + 5 = -21
-11y = -21

Divide each side by '-11'.
y = 1.909090909

Simplifying
y = 1.909090909

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