1(-1/5)x=(-4/5)(5+x)

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Solution for 1(-1/5)x=(-4/5)(5+x) equation: 



1(-1/5)x=(-4/5)(5+x)

We move all terms to the left:

1(-1/5)x-((-4/5)(5+x))=0



Domain of the equation: 5)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5)(5+x))!=0

x∈R



We add all the numbers together, and all the variables

1(-1/5)x-((-4/5)(x+5))=0

We multiply parentheses

-1x^2-((-4/5)(x+5))=0

We multiply parentheses ..

-1x^2-((-4x^2-4/5*5))=0

We multiply all the terms by the denominator


-4x^2-1x^2*5*5))-((-4=0

Wy multiply elements

-4x^2-25x^3*5-4=0

We do not support expression: x^3

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