1(-12z+4)-2=-4(3z-3)-13

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Solution for 1(-12z+4)-2=-4(3z-3)-13 equation: 


Simplifying
1(-12z + 4) + -2 = -4(3z + -3) + -13

Reorder the terms:
1(4 + -12z) + -2 = -4(3z + -3) + -13
(4 * 1 + -12z * 1) + -2 = -4(3z + -3) + -13
(4 + -12z) + -2 = -4(3z + -3) + -13

Reorder the terms:
4 + -2 + -12z = -4(3z + -3) + -13

Combine like terms: 4 + -2 = 2
2 + -12z = -4(3z + -3) + -13

Reorder the terms:
2 + -12z = -4(-3 + 3z) + -13
2 + -12z = (-3 * -4 + 3z * -4) + -13
2 + -12z = (12 + -12z) + -13

Reorder the terms:
2 + -12z = 12 + -13 + -12z

Combine like terms: 12 + -13 = -1
2 + -12z = -1 + -12z

Add '12z' to each side of the equation.
2 + -12z + 12z = -1 + -12z + 12z

Combine like terms: -12z + 12z = 0
2 + 0 = -1 + -12z + 12z
2 = -1 + -12z + 12z

Combine like terms: -12z + 12z = 0
2 = -1 + 0
2 = -1

Solving
2 = -1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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