1(-6b+11)-42=10(-b-2)-8

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Solution for 1(-6b+11)-42=10(-b-2)-8 equation: 



1(-6b+11)-42=10(-b-2)-8

We move all terms to the left:

1(-6b+11)-42-(10(-b-2)-8)=0

We add all the numbers together, and all the variables

1(-6b+11)-(10(-1b-2)-8)-42=0



We calculate terms in parentheses: -(10(-1b-2)-8), so:

10(-1b-2)-8

We multiply parentheses

-10b-20-8

We add all the numbers together, and all the variables

-10b-28

Back to the equation:

-(-10b-28)



We get rid of parentheses

1(-6b+11)+10b+28-42=0

We add all the numbers together, and all the variables

10b+1(-6b+11)-14=0

We move all terms containing b to the left, all other terms to the right

10b+1(-6b+11)=14

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