1(12z-18)=2z-36

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Solution for 1(12z-18)=2z-36 equation: 



1(12z-18)=2z-36

We move all terms to the left:

1(12z-18)-(2z-36)=0

We get rid of parentheses

1(12z-18)-2z+36=0

We add all the numbers together, and all the variables

-2z+1(12z-18)+36=0

We move all terms containing z to the left, all other terms to the right

-2z+1(12z-18)=-36

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