1(16y)=3(y+13)

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Solution for 1(16y)=3(y+13) equation: 



1(16y)=3(y+13)

We move all terms to the left:

1(16y)-(3(y+13))=0



We calculate terms in parentheses: -(3(y+13)), so:

3(y+13)

We multiply parentheses

3y+39

Back to the equation:

-(3y+39)



We get rid of parentheses

116y-3y-39=0

We add all the numbers together, and all the variables

113y-39=0

We move all terms containing y to the left, all other terms to the right

113y=39

y=39/113

y=39/113

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