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1(2)/(5)x=7
We move all terms to the left:
1(2)/(5)x-(7)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
-7*5x+12=0
Wy multiply elements
-35x+12=0
We move all terms containing x to the left, all other terms to the right
-35x=-12
x=-12/-35
x=12/35
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