1(2v+3)-4=12(4v+8)

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Solution for 1(2v+3)-4=12(4v+8) equation: 



1(2v+3)-4=12(4v+8)

We move all terms to the left:

1(2v+3)-4-(12(4v+8))=0



We calculate terms in parentheses: -(12(4v+8)), so:

12(4v+8)

We multiply parentheses

48v+96

Back to the equation:

-(48v+96)



We get rid of parentheses

1(2v+3)-48v-96-4=0

We add all the numbers together, and all the variables

-48v+1(2v+3)-100=0

We move all terms containing v to the left, all other terms to the right

-48v+1(2v+3)=100

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