1(2x+5)=10x+47

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Solution for 1(2x+5)=10x+47 equation: 



1(2x+5)=10x+47

We move all terms to the left:

1(2x+5)-(10x+47)=0

We get rid of parentheses

1(2x+5)-10x-47=0

We add all the numbers together, and all the variables

-10x+1(2x+5)-47=0

We move all terms containing x to the left, all other terms to the right

-10x+1(2x+5)=47

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