1(2y+2)-4=16-8(y+1)

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Solution for 1(2y+2)-4=16-8(y+1) equation:


Simplifying
1(2y + 2) + -4 = 16 + -8(y + 1)

Reorder the terms:
1(2 + 2y) + -4 = 16 + -8(y + 1)
(2 * 1 + 2y * 1) + -4 = 16 + -8(y + 1)
(2 + 2y) + -4 = 16 + -8(y + 1)

Reorder the terms:
2 + -4 + 2y = 16 + -8(y + 1)

Combine like terms: 2 + -4 = -2
-2 + 2y = 16 + -8(y + 1)

Reorder the terms:
-2 + 2y = 16 + -8(1 + y)
-2 + 2y = 16 + (1 * -8 + y * -8)
-2 + 2y = 16 + (-8 + -8y)

Combine like terms: 16 + -8 = 8
-2 + 2y = 8 + -8y

Solving
-2 + 2y = 8 + -8y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '8y' to each side of the equation.
-2 + 2y + 8y = 8 + -8y + 8y

Combine like terms: 2y + 8y = 10y
-2 + 10y = 8 + -8y + 8y

Combine like terms: -8y + 8y = 0
-2 + 10y = 8 + 0
-2 + 10y = 8

Add '2' to each side of the equation.
-2 + 2 + 10y = 8 + 2

Combine like terms: -2 + 2 = 0
0 + 10y = 8 + 2
10y = 8 + 2

Combine like terms: 8 + 2 = 10
10y = 10

Divide each side by '10'.
y = 1

Simplifying
y = 1

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