1(3+x)(6+x)=12x+12

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Solution for 1(3+x)(6+x)=12x+12 equation: 



1(3+x)(6+x)=12x+12

We move all terms to the left:

1(3+x)(6+x)-(12x+12)=0

We add all the numbers together, and all the variables

1(x+3)(x+6)-(12x+12)=0

We get rid of parentheses

1(x+3)(x+6)-12x-12=0

We multiply parentheses ..

1(+x^2+6x+3x+18)-12x-12=0

We move all terms containing x to the left, all other terms to the right

1(+x^2+6x+3x+18)-12x=12

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