1(3-x)=1-(x-2)

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Solution for 1(3-x)=1-(x-2) equation:


Simplifying
1(3 + -1x) = 1 + -1(x + -2)
(3 * 1 + -1x * 1) = 1 + -1(x + -2)
(3 + -1x) = 1 + -1(x + -2)

Reorder the terms:
3 + -1x = 1 + -1(-2 + x)
3 + -1x = 1 + (-2 * -1 + x * -1)
3 + -1x = 1 + (2 + -1x)

Combine like terms: 1 + 2 = 3
3 + -1x = 3 + -1x

Add '-3' to each side of the equation.
3 + -3 + -1x = 3 + -3 + -1x

Combine like terms: 3 + -3 = 0
0 + -1x = 3 + -3 + -1x
-1x = 3 + -3 + -1x

Combine like terms: 3 + -3 = 0
-1x = 0 + -1x
-1x = -1x

Add 'x' to each side of the equation.
-1x + x = -1x + x

Combine like terms: -1x + x = 0
0 = -1x + x

Combine like terms: -1x + x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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