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1(3d-2)=2(d+5)
We move all terms to the left:
1(3d-2)-(2(d+5))=0
We calculate terms in parentheses: -(2(d+5)), so:We get rid of parentheses
2(d+5)
We multiply parentheses
2d+10
Back to the equation:
-(2d+10)
1(3d-2)-2d-10=0
We add all the numbers together, and all the variables
-2d+1(3d-2)-10=0
We move all terms containing d to the left, all other terms to the right
-2d+1(3d-2)=10
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