1(3x+4)=2(x+8)

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Solution for 1(3x+4)=2(x+8) equation: 



1(3x+4)=2(x+8)

We move all terms to the left:

1(3x+4)-(2(x+8))=0



We calculate terms in parentheses: -(2(x+8)), so:

2(x+8)

We multiply parentheses

2x+16

Back to the equation:

-(2x+16)



We get rid of parentheses

1(3x+4)-2x-16=0

We add all the numbers together, and all the variables

-2x+1(3x+4)-16=0

We move all terms containing x to the left, all other terms to the right

-2x+1(3x+4)=16

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