1(3x+9)=2(x+29)

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Solution for 1(3x+9)=2(x+29) equation:



1(3x+9)=2(x+29)
We move all terms to the left:
1(3x+9)-(2(x+29))=0
We calculate terms in parentheses: -(2(x+29)), so:
2(x+29)
We multiply parentheses
2x+58
Back to the equation:
-(2x+58)
We get rid of parentheses
1(3x+9)-2x-58=0
We add all the numbers together, and all the variables
-2x+1(3x+9)-58=0
We move all terms containing x to the left, all other terms to the right
-2x+1(3x+9)=58

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