1(3z+4)=6z-3(3z+2)

Solution for 1(3z+4)=6z-3(3z+2) equation:

Simplifying
1(3z + 4) = 6z + -3(3z + 2)

Reorder the terms:
1(4 + 3z) = 6z + -3(3z + 2)
(4 * 1 + 3z * 1) = 6z + -3(3z + 2)
(4 + 3z) = 6z + -3(3z + 2)

Reorder the terms:
4 + 3z = 6z + -3(2 + 3z)
4 + 3z = 6z + (2 * -3 + 3z * -3)
4 + 3z = 6z + (-6 + -9z)

Reorder the terms:
4 + 3z = -6 + 6z + -9z

Combine like terms: 6z + -9z = -3z
4 + 3z = -6 + -3z

Solving
4 + 3z = -6 + -3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3z' to each side of the equation.
4 + 3z + 3z = -6 + -3z + 3z

Combine like terms: 3z + 3z = 6z
4 + 6z = -6 + -3z + 3z

Combine like terms: -3z + 3z = 0
4 + 6z = -6 + 0
4 + 6z = -6

Add '-4' to each side of the equation.
4 + -4 + 6z = -6 + -4

Combine like terms: 4 + -4 = 0
0 + 6z = -6 + -4
6z = -6 + -4

Combine like terms: -6 + -4 = -10
6z = -10

Divide each side by '6'.
z = -1.666666667

Simplifying
z = -1.666666667