1(4x+16x)+48=2(8-4x)+40

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Solution for 1(4x+16x)+48=2(8-4x)+40 equation: 



1(4x+16x)+48=2(8-4x)+40

We move all terms to the left:

1(4x+16x)+48-(2(8-4x)+40)=0

We add all the numbers together, and all the variables

1(+20x)-(2(-4x+8)+40)+48=0



We calculate terms in parentheses: -(2(-4x+8)+40), so:

2(-4x+8)+40

We multiply parentheses

-8x+16+40

We add all the numbers together, and all the variables

-8x+56

Back to the equation:

-(-8x+56)



We get rid of parentheses

1(+20x)+8x-56+48=0

We add all the numbers together, and all the variables

8x+1(+20x)-8=0

We move all terms containing x to the left, all other terms to the right

8x+1(+20x)=8

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