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1(4x+2)=0x-(2+-4x)
We move all terms to the left:
1(4x+2)-(0x-(2+-4x))=0
We add all the numbers together, and all the variables
1(4x+2)-(0x-(-4x))=0
We calculate terms in parentheses: -(0x-(-4x)), so:We add all the numbers together, and all the variables
0x-(-4x)
We add all the numbers together, and all the variables
x-(-4x)
We get rid of parentheses
x+4x
We add all the numbers together, and all the variables
5x
Back to the equation:
-(5x)
-5x+1(4x+2)=0
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