1(4y-8)=2(y+4)

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Solution for 1(4y-8)=2(y+4) equation: 



1(4y-8)=2(y+4)

We move all terms to the left:

1(4y-8)-(2(y+4))=0



We calculate terms in parentheses: -(2(y+4)), so:

2(y+4)

We multiply parentheses

2y+8

Back to the equation:

-(2y+8)



We get rid of parentheses

1(4y-8)-2y-8=0

We add all the numbers together, and all the variables

-2y+1(4y-8)-8=0

We move all terms containing y to the left, all other terms to the right

-2y+1(4y-8)=8

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