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1(6x+4)=5(2x-8)
We move all terms to the left:
1(6x+4)-(5(2x-8))=0
We calculate terms in parentheses: -(5(2x-8)), so:We get rid of parentheses
5(2x-8)
We multiply parentheses
10x-40
Back to the equation:
-(10x-40)
1(6x+4)-10x+40=0
We add all the numbers together, and all the variables
-10x+1(6x+4)+40=0
We move all terms containing x to the left, all other terms to the right
-10x+1(6x+4)=-40
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