1(7+-2)-1(-3t+1)=-3(1-3t)

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Solution for 1(7+-2)-1(-3t+1)=-3(1-3t) equation: 



1(7+-2)-1(-3t+1)=-3(1-3t)

We move all terms to the left:

1(7+-2)-1(-3t+1)-(-3(1-3t))=0

We add all the numbers together, and all the variables

-1(-3t+1)-(-3(-3t+1))+15=0



We calculate terms in parentheses: -(-3(-3t+1)), so:

-3(-3t+1)

We multiply parentheses

9t-3

Back to the equation:

-(9t-3)



We get rid of parentheses

-1(-3t+1)-9t+3+15=0

We add all the numbers together, and all the variables

-9t-1(-3t+1)+18=0

We move all terms containing t to the left, all other terms to the right

-9t-1(-3t+1)=-18

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