1(710+3y)/7+Y=150

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Solution for 1(710+3y)/7+Y=150 equation: 


x in (-oo:+oo)

(1*(3*y+710))/7+Y = 150 // - 150

(1*(3*y+710))/7+Y-150 = 0

(3*y+710)/7+Y-150 = 0

(3*y+710)/7+(7*Y)/7+(-150*7)/7 = 0

7*Y+3*y-150*7+710 = 0

7*Y+3*y-1050+710 = 0

7*Y+3*y-340 = 0

(7*Y+3*y-340)/7 = 0

(7*Y+3*y-340)/7 = 0 // * 7

7*Y+3*y-340 = 0

x belongs to the empty set

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