1(8n-2)=10(1-3n)+14

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Solution for 1(8n-2)=10(1-3n)+14 equation: 



1(8n-2)=10(1-3n)+14

We move all terms to the left:

1(8n-2)-(10(1-3n)+14)=0

We add all the numbers together, and all the variables

1(8n-2)-(10(-3n+1)+14)=0



We calculate terms in parentheses: -(10(-3n+1)+14), so:

10(-3n+1)+14

We multiply parentheses

-30n+10+14

We add all the numbers together, and all the variables

-30n+24

Back to the equation:

-(-30n+24)



We get rid of parentheses

1(8n-2)+30n-24=0

We add all the numbers together, and all the variables

30n+1(8n-2)-24=0

We move all terms containing n to the left, all other terms to the right

30n+1(8n-2)=24

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