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1(9-x)+x=10x+(9-x)+27
We move all terms to the left:
1(9-x)+x-(10x+(9-x)+27)=0
We add all the numbers together, and all the variables
1(-1x+9)+x-(10x+(-1x+9)+27)=0
We add all the numbers together, and all the variables
x+1(-1x+9)-(10x+(-1x+9)+27)=0
We calculate terms in parentheses: -(10x+(-1x+9)+27), so:We get rid of parentheses
10x+(-1x+9)+27
We get rid of parentheses
10x-1x+9+27
We add all the numbers together, and all the variables
9x+36
Back to the equation:
-(9x+36)
x+1(-1x+9)-9x-36=0
We add all the numbers together, and all the variables
-8x+1(-1x+9)-36=0
We move all terms containing x to the left, all other terms to the right
-8x+1(-1x+9)=36
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