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1(9x+3)/3=3x+1
We move all terms to the left:
1(9x+3)/3-(3x+1)=0
We get rid of parentheses
1(9x+3)/3-3x-1=0
We multiply all the terms by the denominator
1(9x+3)-3x*3-1*3=0
We add all the numbers together, and all the variables
1(9x+3)-3x*3-3=0
Wy multiply elements
1(9x+3)-9x-3=0
We add all the numbers together, and all the variables
-9x+1(9x+3)-3=0
We move all terms containing x to the left, all other terms to the right
-9x+1(9x+3)=3
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