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1(9x-5)-11=2(x+3)
We move all terms to the left:
1(9x-5)-11-(2(x+3))=0
We calculate terms in parentheses: -(2(x+3)), so:We get rid of parentheses
2(x+3)
We multiply parentheses
2x+6
Back to the equation:
-(2x+6)
1(9x-5)-2x-6-11=0
We add all the numbers together, and all the variables
-2x+1(9x-5)-17=0
We move all terms containing x to the left, all other terms to the right
-2x+1(9x-5)=17
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