1(j+1)=5(j-3)

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Solution for 1(j+1)=5(j-3) equation:


Simplifying
1(j + 1) = 5(j + -3)

Reorder the terms:
1(1 + j) = 5(j + -3)
(1 * 1 + j * 1) = 5(j + -3)
(1 + 1j) = 5(j + -3)

Reorder the terms:
1 + 1j = 5(-3 + j)
1 + 1j = (-3 * 5 + j * 5)
1 + 1j = (-15 + 5j)

Solving
1 + 1j = -15 + 5j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-5j' to each side of the equation.
1 + 1j + -5j = -15 + 5j + -5j

Combine like terms: 1j + -5j = -4j
1 + -4j = -15 + 5j + -5j

Combine like terms: 5j + -5j = 0
1 + -4j = -15 + 0
1 + -4j = -15

Add '-1' to each side of the equation.
1 + -1 + -4j = -15 + -1

Combine like terms: 1 + -1 = 0
0 + -4j = -15 + -1
-4j = -15 + -1

Combine like terms: -15 + -1 = -16
-4j = -16

Divide each side by '-4'.
j = 4

Simplifying
j = 4

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