1(m-4)=3(2-m)

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Solution for 1(m-4)=3(2-m) equation: 



1(m-4)=3(2-m)

We move all terms to the left:

1(m-4)-(3(2-m))=0

We add all the numbers together, and all the variables

1(m-4)-(3(-1m+2))=0



We calculate terms in parentheses: -(3(-1m+2)), so:

3(-1m+2)

We multiply parentheses

-3m+6

Back to the equation:

-(-3m+6)



We get rid of parentheses

1(m-4)+3m-6=0

We add all the numbers together, and all the variables

3m+1(m-4)-6=0

We move all terms containing m to the left, all other terms to the right

3m+1(m-4)=6

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