1(n+1)+2(n+2)+3(n+3)=104

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Solution for 1(n+1)+2(n+2)+3(n+3)=104 equation:


Simplifying
1(n + 1) + 2(n + 2) + 3(n + 3) = 104

Reorder the terms:
1(1 + n) + 2(n + 2) + 3(n + 3) = 104
(1 * 1 + n * 1) + 2(n + 2) + 3(n + 3) = 104
(1 + 1n) + 2(n + 2) + 3(n + 3) = 104

Reorder the terms:
1 + 1n + 2(2 + n) + 3(n + 3) = 104
1 + 1n + (2 * 2 + n * 2) + 3(n + 3) = 104
1 + 1n + (4 + 2n) + 3(n + 3) = 104

Reorder the terms:
1 + 1n + 4 + 2n + 3(3 + n) = 104
1 + 1n + 4 + 2n + (3 * 3 + n * 3) = 104
1 + 1n + 4 + 2n + (9 + 3n) = 104

Reorder the terms:
1 + 4 + 9 + 1n + 2n + 3n = 104

Combine like terms: 1 + 4 = 5
5 + 9 + 1n + 2n + 3n = 104

Combine like terms: 5 + 9 = 14
14 + 1n + 2n + 3n = 104

Combine like terms: 1n + 2n = 3n
14 + 3n + 3n = 104

Combine like terms: 3n + 3n = 6n
14 + 6n = 104

Solving
14 + 6n = 104

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 6n = 104 + -14

Combine like terms: 14 + -14 = 0
0 + 6n = 104 + -14
6n = 104 + -14

Combine like terms: 104 + -14 = 90
6n = 90

Divide each side by '6'.
n = 15

Simplifying
n = 15

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