1(n+n+3)=2(-4n+3)

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Solution for 1(n+n+3)=2(-4n+3) equation: 



1(n+n+3)=2(-4n+3)

We move all terms to the left:

1(n+n+3)-(2(-4n+3))=0

We add all the numbers together, and all the variables

1(2n+3)-(2(-4n+3))=0



We calculate terms in parentheses: -(2(-4n+3)), so:

2(-4n+3)

We multiply parentheses

-8n+6

Back to the equation:

-(-8n+6)



We get rid of parentheses

1(2n+3)+8n-6=0

We add all the numbers together, and all the variables

8n+1(2n+3)-6=0

We move all terms containing n to the left, all other terms to the right

8n+1(2n+3)=6

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