1(t-2)+7t=4(2t+3)-8

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Solution for 1(t-2)+7t=4(2t+3)-8 equation: 


Simplifying
1(t + -2) + 7t = 4(2t + 3) + -8

Reorder the terms:
1(-2 + t) + 7t = 4(2t + 3) + -8
(-2 * 1 + t * 1) + 7t = 4(2t + 3) + -8
(-2 + 1t) + 7t = 4(2t + 3) + -8

Combine like terms: 1t + 7t = 8t
-2 + 8t = 4(2t + 3) + -8

Reorder the terms:
-2 + 8t = 4(3 + 2t) + -8
-2 + 8t = (3 * 4 + 2t * 4) + -8
-2 + 8t = (12 + 8t) + -8

Reorder the terms:
-2 + 8t = 12 + -8 + 8t

Combine like terms: 12 + -8 = 4
-2 + 8t = 4 + 8t

Add '-8t' to each side of the equation.
-2 + 8t + -8t = 4 + 8t + -8t

Combine like terms: 8t + -8t = 0
-2 + 0 = 4 + 8t + -8t
-2 = 4 + 8t + -8t

Combine like terms: 8t + -8t = 0
-2 = 4 + 0
-2 = 4

Solving
-2 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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