1(t-2)+7t=4(2t+4)-10

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Solution for 1(t-2)+7t=4(2t+4)-10 equation: 


Simplifying
1(t + -2) + 7t = 4(2t + 4) + -10

Reorder the terms:
1(-2 + t) + 7t = 4(2t + 4) + -10
(-2 * 1 + t * 1) + 7t = 4(2t + 4) + -10
(-2 + 1t) + 7t = 4(2t + 4) + -10

Combine like terms: 1t + 7t = 8t
-2 + 8t = 4(2t + 4) + -10

Reorder the terms:
-2 + 8t = 4(4 + 2t) + -10
-2 + 8t = (4 * 4 + 2t * 4) + -10
-2 + 8t = (16 + 8t) + -10

Reorder the terms:
-2 + 8t = 16 + -10 + 8t

Combine like terms: 16 + -10 = 6
-2 + 8t = 6 + 8t

Add '-8t' to each side of the equation.
-2 + 8t + -8t = 6 + 8t + -8t

Combine like terms: 8t + -8t = 0
-2 + 0 = 6 + 8t + -8t
-2 = 6 + 8t + -8t

Combine like terms: 8t + -8t = 0
-2 = 6 + 0
-2 = 6

Solving
-2 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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