1(t-3)+7t=4(2t+3)-10

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Solution for 1(t-3)+7t=4(2t+3)-10 equation: 


Simplifying
1(t + -3) + 7t = 4(2t + 3) + -10

Reorder the terms:
1(-3 + t) + 7t = 4(2t + 3) + -10
(-3 * 1 + t * 1) + 7t = 4(2t + 3) + -10
(-3 + 1t) + 7t = 4(2t + 3) + -10

Combine like terms: 1t + 7t = 8t
-3 + 8t = 4(2t + 3) + -10

Reorder the terms:
-3 + 8t = 4(3 + 2t) + -10
-3 + 8t = (3 * 4 + 2t * 4) + -10
-3 + 8t = (12 + 8t) + -10

Reorder the terms:
-3 + 8t = 12 + -10 + 8t

Combine like terms: 12 + -10 = 2
-3 + 8t = 2 + 8t

Add '-8t' to each side of the equation.
-3 + 8t + -8t = 2 + 8t + -8t

Combine like terms: 8t + -8t = 0
-3 + 0 = 2 + 8t + -8t
-3 = 2 + 8t + -8t

Combine like terms: 8t + -8t = 0
-3 = 2 + 0
-3 = 2

Solving
-3 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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