1(t-3)+7t=4(2t+4)-8

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Solution for 1(t-3)+7t=4(2t+4)-8 equation: 


Simplifying
1(t + -3) + 7t = 4(2t + 4) + -8

Reorder the terms:
1(-3 + t) + 7t = 4(2t + 4) + -8
(-3 * 1 + t * 1) + 7t = 4(2t + 4) + -8
(-3 + 1t) + 7t = 4(2t + 4) + -8

Combine like terms: 1t + 7t = 8t
-3 + 8t = 4(2t + 4) + -8

Reorder the terms:
-3 + 8t = 4(4 + 2t) + -8
-3 + 8t = (4 * 4 + 2t * 4) + -8
-3 + 8t = (16 + 8t) + -8

Reorder the terms:
-3 + 8t = 16 + -8 + 8t

Combine like terms: 16 + -8 = 8
-3 + 8t = 8 + 8t

Add '-8t' to each side of the equation.
-3 + 8t + -8t = 8 + 8t + -8t

Combine like terms: 8t + -8t = 0
-3 + 0 = 8 + 8t + -8t
-3 = 8 + 8t + -8t

Combine like terms: 8t + -8t = 0
-3 = 8 + 0
-3 = 8

Solving
-3 = 8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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