1(t-4)+7t=4(2t+4)-11

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Solution for 1(t-4)+7t=4(2t+4)-11 equation:


Simplifying
1(t + -4) + 7t = 4(2t + 4) + -11

Reorder the terms:
1(-4 + t) + 7t = 4(2t + 4) + -11
(-4 * 1 + t * 1) + 7t = 4(2t + 4) + -11
(-4 + 1t) + 7t = 4(2t + 4) + -11

Combine like terms: 1t + 7t = 8t
-4 + 8t = 4(2t + 4) + -11

Reorder the terms:
-4 + 8t = 4(4 + 2t) + -11
-4 + 8t = (4 * 4 + 2t * 4) + -11
-4 + 8t = (16 + 8t) + -11

Reorder the terms:
-4 + 8t = 16 + -11 + 8t

Combine like terms: 16 + -11 = 5
-4 + 8t = 5 + 8t

Add '-8t' to each side of the equation.
-4 + 8t + -8t = 5 + 8t + -8t

Combine like terms: 8t + -8t = 0
-4 + 0 = 5 + 8t + -8t
-4 = 5 + 8t + -8t

Combine like terms: 8t + -8t = 0
-4 = 5 + 0
-4 = 5

Solving
-4 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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