1(t-4)+7t=4(2t+5)-12

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Solution for 1(t-4)+7t=4(2t+5)-12 equation:



1(t-4)+7t=4(2t+5)-12
We move all terms to the left:
1(t-4)+7t-(4(2t+5)-12)=0
We add all the numbers together, and all the variables
7t+1(t-4)-(4(2t+5)-12)=0
We calculate terms in parentheses: -(4(2t+5)-12), so:
4(2t+5)-12
We multiply parentheses
8t+20-12
We add all the numbers together, and all the variables
8t+8
Back to the equation:
-(8t+8)
We get rid of parentheses
7t+1(t-4)-8t-8=0
We add all the numbers together, and all the variables
-1t+1(t-4)-8=0
We move all terms containing t to the left, all other terms to the right
-1t+1(t-4)=8

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