1(t-5)+7t=4(2t+5)-10

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Solution for 1(t-5)+7t=4(2t+5)-10 equation: 



1(t-5)+7t=4(2t+5)-10

We move all terms to the left:

1(t-5)+7t-(4(2t+5)-10)=0

We add all the numbers together, and all the variables

7t+1(t-5)-(4(2t+5)-10)=0



We calculate terms in parentheses: -(4(2t+5)-10), so:

4(2t+5)-10

We multiply parentheses

8t+20-10

We add all the numbers together, and all the variables

8t+10

Back to the equation:

-(8t+10)



We get rid of parentheses

7t+1(t-5)-8t-10=0

We add all the numbers together, and all the variables

-1t+1(t-5)-10=0

We move all terms containing t to the left, all other terms to the right

-1t+1(t-5)=10

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