1(t-5)+7t=4(2t+5)-8

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Solution for 1(t-5)+7t=4(2t+5)-8 equation: 


Simplifying
1(t + -5) + 7t = 4(2t + 5) + -8

Reorder the terms:
1(-5 + t) + 7t = 4(2t + 5) + -8
(-5 * 1 + t * 1) + 7t = 4(2t + 5) + -8
(-5 + 1t) + 7t = 4(2t + 5) + -8

Combine like terms: 1t + 7t = 8t
-5 + 8t = 4(2t + 5) + -8

Reorder the terms:
-5 + 8t = 4(5 + 2t) + -8
-5 + 8t = (5 * 4 + 2t * 4) + -8
-5 + 8t = (20 + 8t) + -8

Reorder the terms:
-5 + 8t = 20 + -8 + 8t

Combine like terms: 20 + -8 = 12
-5 + 8t = 12 + 8t

Add '-8t' to each side of the equation.
-5 + 8t + -8t = 12 + 8t + -8t

Combine like terms: 8t + -8t = 0
-5 + 0 = 12 + 8t + -8t
-5 = 12 + 8t + -8t

Combine like terms: 8t + -8t = 0
-5 = 12 + 0
-5 = 12

Solving
-5 = 12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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