1(t-5)=-12.2(4-t)

Solution for 1(t-5)=-12.2(4-t) equation:

1(t-5)=-12.2(4-t)

We move all terms to the left:

1(t-5)-(-12.2(4-t))=0

We add all the numbers together, and all the variables

1(t-5)-(-12.2(-1t+4))=0


We calculate terms in parentheses: -(-12.2(-1t+4)), so:

-12.2(-1t+4)

We multiply parentheses

12.2t-48.8

Back to the equation:

-(12.2t-48.8)


We get rid of parentheses

1(t-5)-12.2t+48.8=0

We add all the numbers together, and all the variables

-12.2t+1(t-5)+48.8=0

We move all terms containing t to the left, all other terms to the right

-12.2t+1(t-5)=-48.8