1(t-6)+7t=4(2t+4)-8

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Solution for 1(t-6)+7t=4(2t+4)-8 equation: 



1(t-6)+7t=4(2t+4)-8

We move all terms to the left:

1(t-6)+7t-(4(2t+4)-8)=0

We add all the numbers together, and all the variables

7t+1(t-6)-(4(2t+4)-8)=0



We calculate terms in parentheses: -(4(2t+4)-8), so:

4(2t+4)-8

We multiply parentheses

8t+16-8

We add all the numbers together, and all the variables

8t+8

Back to the equation:

-(8t+8)



We get rid of parentheses

7t+1(t-6)-8t-8=0

We add all the numbers together, and all the variables

-1t+1(t-6)-8=0

We move all terms containing t to the left, all other terms to the right

-1t+1(t-6)=8

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