1(v-45)=2(v-68)

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Solution for 1(v-45)=2(v-68) equation:



1(v-45)=2(v-68)
We move all terms to the left:
1(v-45)-(2(v-68))=0
We calculate terms in parentheses: -(2(v-68)), so:
2(v-68)
We multiply parentheses
2v-136
Back to the equation:
-(2v-136)
We get rid of parentheses
1(v-45)-2v+136=0
We add all the numbers together, and all the variables
-2v+1(v-45)+136=0
We move all terms containing v to the left, all other terms to the right
-2v+1(v-45)=-136

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