1(v-45)=2(v-68)

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Solution for 1(v-45)=2(v-68) equation: 



1(v-45)=2(v-68)

We move all terms to the left:

1(v-45)-(2(v-68))=0



We calculate terms in parentheses: -(2(v-68)), so:

2(v-68)

We multiply parentheses

2v-136

Back to the equation:

-(2v-136)



We get rid of parentheses

1(v-45)-2v+136=0

We add all the numbers together, and all the variables

-2v+1(v-45)+136=0

We move all terms containing v to the left, all other terms to the right

-2v+1(v-45)=-136

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