1(w-4)=4(w+4)+4w

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Solution for 1(w-4)=4(w+4)+4w equation: 



1(w-4)=4(w+4)+4w

We move all terms to the left:

1(w-4)-(4(w+4)+4w)=0



We calculate terms in parentheses: -(4(w+4)+4w), so:

4(w+4)+4w

We add all the numbers together, and all the variables

4w+4(w+4)

We multiply parentheses

4w+4w+16

We add all the numbers together, and all the variables

8w+16

Back to the equation:

-(8w+16)



We get rid of parentheses

1(w-4)-8w-16=0

We add all the numbers together, and all the variables

-8w+1(w-4)-16=0

We move all terms containing w to the left, all other terms to the right

-8w+1(w-4)=16

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