1(x+1)+3(x-1)=5(x+1)

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Solution for 1(x+1)+3(x-1)=5(x+1) equation: 



1(x+1)+3(x-1)=5(x+1)

We move all terms to the left:

1(x+1)+3(x-1)-(5(x+1))=0

We multiply parentheses

1(x+1)+3x-(5(x+1))-3=0



We calculate terms in parentheses: -(5(x+1)), so:

5(x+1)

We multiply parentheses

5x+5

Back to the equation:

-(5x+5)



We add all the numbers together, and all the variables

3x+1(x+1)-(5x+5)-3=0

We get rid of parentheses

3x+1(x+1)-5x-5-3=0

We add all the numbers together, and all the variables

-2x+1(x+1)-8=0

We move all terms containing x to the left, all other terms to the right

-2x+1(x+1)=8

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