1(x+2)+8=-7(x+4)

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Solution for 1(x+2)+8=-7(x+4) equation: 



1(x+2)+8=-7(x+4)

We move all terms to the left:

1(x+2)+8-(-7(x+4))=0



We calculate terms in parentheses: -(-7(x+4)), so:

-7(x+4)

We multiply parentheses

-7x-28

Back to the equation:

-(-7x-28)



We get rid of parentheses

1(x+2)+7x+28+8=0

We add all the numbers together, and all the variables

7x+1(x+2)+36=0

We move all terms containing x to the left, all other terms to the right

7x+1(x+2)=-36

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