1(x+4)+3=-8(x-2)

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Solution for 1(x+4)+3=-8(x-2) equation: 



1(x+4)+3=-8(x-2)

We move all terms to the left:

1(x+4)+3-(-8(x-2))=0



We calculate terms in parentheses: -(-8(x-2)), so:

-8(x-2)

We multiply parentheses

-8x+16

Back to the equation:

-(-8x+16)



We get rid of parentheses

1(x+4)+8x-16+3=0

We add all the numbers together, and all the variables

8x+1(x+4)-13=0

We move all terms containing x to the left, all other terms to the right

8x+1(x+4)=13

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