1(x+5)-(5(x-2))=7

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Solution for 1(x+5)-(5(x-2))=7 equation:


Simplifying
1(x + 5) + -1(5(x + -2)) = 7

Reorder the terms:
1(5 + x) + -1(5(x + -2)) = 7
(5 * 1 + x * 1) + -1(5(x + -2)) = 7
(5 + 1x) + -1(5(x + -2)) = 7

Reorder the terms:
5 + 1x + -1(5(-2 + x)) = 7
5 + 1x + -1((-2 * 5 + x * 5)) = 7
5 + 1x + -1((-10 + 5x)) = 7
5 + 1x + (-10 * -1 + 5x * -1) = 7
5 + 1x + (10 + -5x) = 7

Reorder the terms:
5 + 10 + 1x + -5x = 7

Combine like terms: 5 + 10 = 15
15 + 1x + -5x = 7

Combine like terms: 1x + -5x = -4x
15 + -4x = 7

Solving
15 + -4x = 7

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-15' to each side of the equation.
15 + -15 + -4x = 7 + -15

Combine like terms: 15 + -15 = 0
0 + -4x = 7 + -15
-4x = 7 + -15

Combine like terms: 7 + -15 = -8
-4x = -8

Divide each side by '-4'.
x = 2

Simplifying
x = 2

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