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1(x+5)=5x+3(x+4)
We move all terms to the left:
1(x+5)-(5x+3(x+4))=0
We calculate terms in parentheses: -(5x+3(x+4)), so:We get rid of parentheses
5x+3(x+4)
We multiply parentheses
5x+3x+12
We add all the numbers together, and all the variables
8x+12
Back to the equation:
-(8x+12)
1(x+5)-8x-12=0
We add all the numbers together, and all the variables
-8x+1(x+5)-12=0
We move all terms containing x to the left, all other terms to the right
-8x+1(x+5)=12
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