1(x-2)+1/x=8/2x+5

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Solution for 1(x-2)+1/x=8/2x+5 equation: 



1(x-2)+1/x=8/2x+5

We move all terms to the left:

1(x-2)+1/x-(8/2x+5)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: 2x+5)!=0

x∈R



We get rid of parentheses

1(x-2)+1/x-8/2x-5=0

We calculate fractions


1(x-2)+2x/2x^2+(-8x)/2x^2-5=0

We multiply all the terms by the denominator


(1(x-2))*2x^2+2x+(-8x)-5*2x^2=0

We add all the numbers together, and all the variables

2x+(1(x-2))*2x^2+(-8x)-5*2x^2=0

Wy multiply elements

-10x^2+2x+(1(x-2))*2x^2+(-8x)=0

We get rid of parentheses

-10x^2+2x+(1(x-2))*2x^2-8x=0

We add all the numbers together, and all the variables

-10x^2-6x+(1(x-2))*2x^2=0

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