1(x-2)+7x=4(2x+5)-13

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Solution for 1(x-2)+7x=4(2x+5)-13 equation: 


Simplifying
1(x + -2) + 7x = 4(2x + 5) + -13

Reorder the terms:
1(-2 + x) + 7x = 4(2x + 5) + -13
(-2 * 1 + x * 1) + 7x = 4(2x + 5) + -13
(-2 + 1x) + 7x = 4(2x + 5) + -13

Combine like terms: 1x + 7x = 8x
-2 + 8x = 4(2x + 5) + -13

Reorder the terms:
-2 + 8x = 4(5 + 2x) + -13
-2 + 8x = (5 * 4 + 2x * 4) + -13
-2 + 8x = (20 + 8x) + -13

Reorder the terms:
-2 + 8x = 20 + -13 + 8x

Combine like terms: 20 + -13 = 7
-2 + 8x = 7 + 8x

Add '-8x' to each side of the equation.
-2 + 8x + -8x = 7 + 8x + -8x

Combine like terms: 8x + -8x = 0
-2 + 0 = 7 + 8x + -8x
-2 = 7 + 8x + -8x

Combine like terms: 8x + -8x = 0
-2 = 7 + 0
-2 = 7

Solving
-2 = 7

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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